Search Results

@denne I'm not sure if this is right but here goes:A drives one lap at 60km/h, while B drives 2 laps at 120 km/h, they finish at the same time. A is one lap behind B. He would need to drive his second lap in exactly 0 seconds to catch up and make his average the same as B.answer is infinite 180 would work if there were 4 laps and he would drive 180 as long as he drove 60: 1*60(1 lap)+1*180(3 laps) = 2*120(2*2 laps)

Found the N (Hidden Content)

40 (Hidden Content)